22nd question please. Thank you :)
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the value of sin A and cos A is less than 1. why
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AngleDAB=95*
Angle DCB=180*-95*=85*
Since BE parallel to DC,
AngleBCD is equal to angleCBE=85*
Angle FBC=20*+85*=105*
AngleADC=AngleFBC=105*(an exterior angle of quadrilateral is equal to interior opp angle)
Angle DCB=180*-95*=85*
Since BE parallel to DC,
AngleBCD is equal to angleCBE=85*
Angle FBC=20*+85*=105*
AngleADC=AngleFBC=105*(an exterior angle of quadrilateral is equal to interior opp angle)
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