Math, asked by DurvaWagh, 6 months ago

23) A bag contains 10 p. 25p and 50p coins. The number of 25p coins is three
times the number of 10p coins. If 50p coins are 5 more than 25p coins and the
total value of the money in the bag is 120. Find the number of 10p coins. In this
sum. if the number of 10p coins is x then the number of 25p coins and 50p coins
respectiply.​

Answers

Answered by gauripatel99
0

Answer:

Friends…!

Let the rational between the number of coins be y

Thus, the number of 50p, 25p and 10p coins will be 5y, 9y and 4y

Total value of 50 p coin = value of one coin × number of coins

= Rs 0.50 × 5y = Rs 2.50y

Similarly, total value of 25p coin

= Rs 0.25 × 9y = Rs 2.25y

And total value of 10p coins

= Rs 0.10 × 4y = Rs 0.40y

Total values of all coins put together

= Rs (2.50y + 2.25y + 0.40y) = Rs 5.15y

According to the statement, the total value of all coins is Rs 206

Hence, 5.15y = 206

y = 206/ 5.15

y = 40

The rational is 40

The ratio of 50 p coin is 2.50y, thus

= 2.50 × 40= 100

The ratio of 25 p coin is 2.25y, thus

= 2.25 × 40 = 90

The ratio of 10 p coin is 0.40y, thus

= 0.40 × 40 = 16

Number of 50 p coin = 100/0.50 = 200 Nos.

Number of 25p coin = 90/0.25 = 360 Nos.

Number of 10p coin = 16 /0.10= 160 Nos

Answer the number of 50p,25p and 10p coins in the purse are 200, 360 and 160 coins respectively

Thus, value of 0.50 p, 0.25p and 0.10p coins would be Rs 100, Rs 90 and Rs 16 respectively

Total value = Rs (100 + 90 + 16) = Rs 206

Means answer is correct.

Hope this helps....!

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