Question

23) A body of mass 60 Kg is moving with a velocity of 50 m/s. What will be 2 points
the change in kinetic energy if the velocity is halved?​

Answer 1

Here's your answer:

Mass=60kg

velocity = 50m/s

K.E = ½mv²

=½ × 60× 50²

= 75000

If the velocity is halved:

v = ½v

=½ × 50

= 25m/s

K.E = ½mv²

=½ × 60 × 25²

= 18750

Hope you understood!!