Physics, asked by aravindreddy31788, 2 months ago

23
A spring of stiffness 1 kN/m is attached
to a block of mass 4 kg on a surface that
has frictional co-efficient 0.4. The spring
is compressed and released, and the
block accelerates at 2 m/s2 just as it is
released. The work done in compressing
the spring is:​

Answers

Answered by nirman95
1

Given:

A spring of stiffness 1 kN/m is attached to a block of mass 4 kg on a surface that has frictional co-efficient 0.4. The spring is compressed and released, and the block accelerates at 2 m/s2 just as it is released.

To find:

Work done in compressing spring ?

Calculation:

  • Let's say that spring is compressed by x distance !

According to FBD :

 \rm f_{spring}  - friction = ma

 \rm \implies \: kx -  \mu(mg) = ma

 \rm \implies \: 1000x - 0.4(40) = 4 \times 2

 \rm \implies \: 1000x - 0.4(40) = 8

 \rm \implies \: 1000x - 16= 8

 \rm \implies \: 1000x  = 24

 \rm \implies \: x  = 0.024 \: m

Now, work done in compressing is :

 \rm \: W =  \dfrac{1}{2} k {x}^{2}

 \rm  \implies\: W =  \dfrac{1}{2} \times 1000 \times  {(\dfrac{24}{1000} )}^{2}

 \rm  \implies\: W =  \dfrac{576}{2000}

 \rm  \implies\: W =  0.288 \: joule

So , work done is 0.288 J.

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