Question

23. An alpha particle enters a hollow tube of 4m length with an initial speed of 1 km/s. It is accelerated in the tube and comes out of it with a speed of 9 km/s. calculate the time for which it remains inside the tube.​

Answer 1

Answer:

hey its answer

Explanation:

i hope its good

Answer 2

Initial speed, u=1 km/s=1000 m/s

Final speed, v=9 km/s=9000 m/s

By using the relation

v

2

=u

2

+2as

(9000)

2

=(1000)

2

+2×a×4

a=10

7

m/s

2

∴ the time for which the particle remains in the tube

v=u+at

or t=

a

v−u

=

10

7

9000−1000

=8×10 -⁴s

hope this help