Question

23. Calculate the length of a seconds' pendulum
at a place where g = 9.8 m/square second
into​

Answer 1

The length of a second's pendulum at a place where g = 9.8m/s 2 is 90.2 cm

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Answer 2

Given :-

For seconds pendulum T = $2$ secs  

g = $9.8 m/s^{2}$

 

Formula to be used :-

T = $2\pi \sqrt\frac{l}{g}$

⇒ l =   $\frac{gt^{2} }{4\pi^{2} }$

⇒ $\frac{9.8X2^{2} }{4X(3.14)^{2} }$

⇒ $0.994$ m

So  length of simple pendulum is $0.994$ m

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