Math, asked by harshitsaxena1882006, 11 months ago

23. Determine the set of values of p for which the quadratic equation px square
+ 6x + 1 = 0 has
real roots.​

Answers

Answered by SreeragSunil
4

Answer:

p can have values less than 9

Step-by-step explanation:

px^2 +6x+1 = 0 has real roots means

b^2 - 4ac must be greater than 0.

6^2 - 4*p*1>0

36-4p>0

36>4p

p< 9

Answer is the set of values less than 9

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