Question

23. Find a quadratic polynomial, the sum and product of whose zeroes are -3 and 2 respectively​

Answer 1

Answer:

xsq + x - 6

Step-by-step explanation:

formula = xsq - (sum of zeroes) x + product of zeroes

Answer 2

$\large \sf \underline{ \underline{ \: Given : \: \: \: }}$

Sum of roots (α + β) = - 3

Product of roots (α × β) = 2

$\large \sf \underline{ \underline{ \:Solution : \: \: \: }}$

We know that , the quadratic equation is given by

$\large \fbox{ \fbox{ \sf \: {x}^{2} - x(sum \: of \: roots) + (product \: of \: roots) = 0}}$

Substitute the values , we obtain

$\sf \implies {x}^{2} - x \bigg( - 3 \bigg) + 2 = 0 \\ \\ \sf \implies {x}^{2} + 3x + 2 = 0$

Hence , the quadratic polynomial is x² + 3x + 2