Question

23 Find p(0),p(1) of the polynomial
p(y)=(y+2) (y-2)​

Answer 1

Answer:

p(0)=-4 and p(1)=-3

Step-by-step explanation:

p(0)=(0+2)(0-2)

=2×(-2)

=-4

p(1)=(1+2)(1-2)

=3×(-1)

=-3