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Answer:
☆<A+<C=180°
2<A+30°=<C
<A+2<A+30°=180°
3<A+30°=180°
3<A=180°-30°=150°
<A=150/3=50°
<C=180-50=130°
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▪Da recent aayi nee ask cheytha oru questioninu enik complete aayi answer cheyyan pattiyilla.. athinte question njan attatch cheyyunnund...athinte answer below kodukkunnu:
i)We know that, if the line from an angle of a triangle which is perpendicular to the opposite side meets the opposite side at its midpoint ,then the triangle is isosceles
As per this,the given triangle ABC isosceles
Then,AB=AC=10cm
ii) Perimeter=AB+AC+BC=10+10+(6+6)
=32cm
iii)Area= 1/2bh
height=AD
Using pythagoras theorem,
AD=root of AB^2-BD^2=root 10^2-6^2=root 100-36= root 64 = 8cm
Area=1/2bh=1/2×12×8= 6×8 = 48sq.cm
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