Question

23 Find the quadratic polynomial whose zeroes are 2
and –6, respectively. Verify the relation between the
coefficients and zeroes of the polynomial. CBSE 2010​

Plz Solve This Question.

Answer 1

Answer:

Zeros of quadratic equation = 2 and -6

we know that

x^2 -(alpha +beta) x+product of alpha beta

Therefore

=x^2-[2+(-6)]x+2*-6

=x^2+4x-12

The quadratic equation is x^2+4x-12.

x^2+4x-12

=x^2+6x-2x-12

=x(x+6)-2(x-6)

=(x-2)(x+6)

therefore, x=2

x=-6

a=1

b=4

c=-12

sum of zeros

2+(-6) = -b/a

-4 = -4/1

-4 = -4

product of zeros

2*-6 = c/a

-12 = -12

Hence ,

All done.