Question

23, If sin (A+B) = 1 and cos (A-B) = 1, 0º < (A+B) < 90° and A > B, then
find A and B.​

Answer 1

Step-by-step explanation:

sin (A+B)=1

sin(A+B)=sin90°

A+B=90° (1)

and, cos (A-B)=1

cos(A-B)=cos0°

A-B=0° (2)

Adding the both equations, we get

2A=90°

A=45°

Subtracting equation (2) from (1), we get

2B=90°

B=45°

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