Question

23. In AABD, ZA + B = 125 and A+ C = 113, find 2A, 2B and C.​

Answer 1

Step-by-step explanation:

Given that :-

In ∆ABC,

A+B=125.......(1)

A+C=113.......(2)

---------------------

2A+B+C=238.....(3)

-------------------

B+C=238-2A.......(4)

We know that The sum of all angles in a triangle is 180°

A+B+C=180°

=>A+238-2A=180

=>-A=180-238

=>-A=-58

=>A=58

=>2A=2×58

=>2A=116°

from (4)

B+C=238-116=122.....(5)

from (1) and (2)

(1)-(2)= B-C=12....(6)

from (5)&(6)

B+C=122

B-C=12

..................

2B=134

...................

B=134/2=67

from (6)

67-C=12

=>C=67-12=55

answer:-

2A=116°

2B=134°

C=55°