Question

(23.
In Figure-5, a tent is in the shape of a cylinder surmounted by a conical
top. The cylindrical part is 2.1 m high and conical part has slant height
2.8 m. Both the parts have same radius 2 m. Find the area of the canvas
22,
.
​

Answer 1

Answer:

find the area of cone then add the area of cylinder

you'll get the area of tent

use the formula in your book

Answer 2

The area of canvas=$44 m^2$

Step-by-step explanation:

Height of cylinderical part=h=2.1 m

Slant height of conical part=l=2.8 m

Radius=r=2 m

Area of canvas=Curved surface area of cylinder+curved surface area of conical part

Area of canvas=$2\pi rh+\pi r l$

Where $\pi=\frac{22}{7}$

Substitute the values

Area of canvas=$2\times \frac{22}{7}\times 2\times 2.1+\frac{22}{7}\times 2\times 2.8$

Area of canvas=$44 m^2$

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