23. In the adjoining figure, ABCD is a cyclic quadrilateral whose
diagonals intersect at P. If ZDBC = 80° and ZBAC = 40°, find
ZBCD.
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1
Answer:
Answer is 100°
Step-by-step explanation:
Consider ∠CAD and ∠CBD
They are both angles made by the same chord CD
⟹∠CAD=∠CBD=30
∘
Since ABCD is a cyclic quadrilateral opposite angles are supplementary.
⟹∠DAB+∠DCB=180
∘
∠DCB=180
∘
–(∠DAC+∠CAB)
∠DCB=180
o
–30
o
–50
o
=100 ∘
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