Question

23. Point P(x, y) is equidistant from the points A(-2,0) and B(3,-4). Prove that
101-8y=21​

Answer 1

Answer:

proved

Step-by-step explanation:

using distance formula,

Answer 2

BY USING DISTANCE FORMULA:

PA = PB

√(x+2)² + (y - 0)²  =    √(x-3)² + (y + 4)²

x² + 4x + 4 + y²     =     x² - 6x + 9 + y² +8y +16

4x + 4   =    - 6x + 25 + 8y

10x - 8y = 21

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