Question

A particle is moving with speed V in a straight line if the particle starts decelerating with an acceleration a and then it achieved same speed after the time​

Answer 1

Answer:

2times the time required to come to minimum speed to b acquired

Answer 2

Answer:

$\frac{2v}{a}$

Explanation:

Initial speed of the particle $=v$

The retardation of the particle $=-a$

Let in time t, its velocity will be v again

But since it will be in the opposite direction of v, the sign will be negative

Using the first equation of motion

$\boxed{v=u+at}$

$-v=v-at$

$\implies 2v=at$

$\implies t=\frac{2v}{a}$

Hope this helps.