23. Represent v5 on number line
24. Verify that x'+y' = (x+y) (x²-xyty?)
Answers
Answer:
To prove: x
3
−y
3
=(x−y)(x
2
+xy+y
2
)
Consider the right hand side (RHS) and expand it as follows:
(x−y)(x
2
+xy+y
2
)=x
3
+x
2
y+xy
2
−yx
2
−xy
2
−y
3
=(x
3
−y
3
)+(x
2
y+xy
2
+x
2
y−xy
2
)=x
3
−y
3
=LHS
Hence proved.
Yes, we can call it as an identity: For example:
Let us take x=2 and y=1 in x
3
−y
3
=(x−y)(x
2
+xy+y
2
) then the LHS and RHS will be equal as shown below:
2
3
−1
3
=7 and
(2−1)(2
2
+(2×1)+1
2
)=1(5+2)=1×7=7
Therefore, LHS=RHS
Hence, x
3
−y
3
=(x−y)(x
2
+xy+y
2
) can be used as an identity.
Step-by-step explanation:
uhh It took my 10 minutes but it's good I could help you...
Answer:
To prove: x
3
−y
3
=(x−y)(x
2
+xy+y
2
)
Consider the right hand side (RHS) and expand it as follows:
(x−y)(x
2
+xy+y
2
)=x
3
+x
2
y+xy
2
−yx
2
−xy
2
−y
3
=(x
3
−y
3
)+(x
2
y+xy
2
+x
2
y−xy
2
)=x
3
−y
3
=LHS
Hence proved.
Yes, we can call it as an identity: For example:
Let us take x=2 and y=1 in x
3
−y
3
=(x−y)(x
2
+xy+y
2
) then the LHS and RHS will be equal as shown below:
2
3
−1
3
=7 and
(2−1)(2
2
+(2×1)+1
2
)=1(5+2)=1×7=7
Therefore, LHS=RHS
Hence, x
3
−y
3
=(x−y)(x
2
+xy+y
2
) can be used as an identity.
Step-by-step explanation:
uhh It took my 10 minutes but it's good I could help you...