Science, asked by shoebshaikh10092003, 10 months ago

23. The amount of sulphuric acid required to prepare 500 mL of its 0.1N solution is
(1) 4.9 g
(2) 10.5 g
(3) 2.45 g (4) 100 g

Answers

Answered by ankurboruah9365

0

Answer:

10.5 g

Explanation:

hope the answer help you

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