Science, asked by shubham4713c, 4 months ago

23. The setups shown below to study the
reaction of zinc with sodium hydroxide.

Answers

Answered by ketki2007
1

Answer:

Answer: The reactions are given below.

We need to write the reaction of Zinc with dilute HCl and with dilute NaOH and the reaction of sodium carbonate with dilute HCl and dilute NaOH.

Reaction of Zinc metal with dilute HCl and dilute NaOH:

With HCl: It will produce zinc chloride and release hydrogen gas.

Zn+2HCl(aq.)arrow ZnCl_2(aq.)+H_2(g)Zn+2HCl(aq.)arrowZnCl

2

(aq.)+H

2

(g)

With NaOH: this metal will produce a salt named as sodium zincate and will release hydrogen gas.

Zn(s)+2NaOHarrow Na_2ZnO_2(aq.)+H_2(g)Zn(s)+2NaOHarrowNa

2

ZnO

2

(aq.)+H

2

(g)

Reaction of sodium carbonate with dilute HCl and dilute NaOH.

With HCl: It will produce a salt named as sodium chloride and release carbon dioxide gas.

Na_2CO_3(s)+2HCl(aq.)arrow 2NaCl(aq.)+H_2O(l)+CO_2(g)Na

2

CO

3

(s)+2HCl(aq.)arrow2NaCl(aq.)+H

2

O(l)+CO

2

(g)

With NaOH: As, both the compounds are bases, hence no reaction will take place between them.

Na_2CO_3(s)+NaOH(aq.)arrow \text{No reaction}Na

2

CO

3

(s)+NaOH(aq.)arrowNo reaction

Hope it helps you......

Answered by krishnajagtap245
0

Answer:

IV Figure is the correct Ans.

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