23. Two concentric circles are of radi 5 cm and 3 cm. Find the length of the chord of the
larger circle which touches the smaller circle
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Answer:
8cm
Step-by-step explanation:
In the fig. OA =OC=5cm
OB=3cm
In triangle OAB,
AB^2=OA^2-OB^2
=(5)^2-(3)^2
=25-9=16
AB=4cm
Similarly, BD=4cm
From the fig, AD is the chord of the larger circle which touches the smaller circle.
ie, AD=AB+BD
=4+4=8cm
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