Question

233838
(13)
while stirring and answer the following
Take a small amount of copper oxide in a beaker. Add dilute hydrochloric acid slowly and then what is the colour of this solution?​

Answer 1

Answer in two methods:

1st method:

CuO + HCl → CuCl2 + H2O

The colour of the solution will change to blue-green due to the formation of copper chloride.

Copper oxide has changed to copper chloride.

2nd method:

● Answer -

Colour of solution changes to bluish-green due to CuCl2 formation.

CuO(aq) + HCl(l) → CuCl2(aq) + H2O(l)

● Explaination -

Copper oxide reacts with hydrochloric acid to form copper chloride & water.

CuO(aq) + HCl(l) → CuCl2(aq) + H2O(l)

This CuCl2 formed changes solution to blueish green colour.

HOPE IT HELPS YOU.

Explanation:

Answer 2

Explanation:

Answer:

1986

False

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True

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Explanation: