2352 m + 1386 m + 2464 m2 = 6202
Hence, the area of the total field is 6202 m.
unless otherwise stated.)
the area of each of the following combined figures:
figur
7
he tol
6 cm
22.6
3
16 cm
2
7 cm
O
3
12 cm
I la
4 cm
5 cm
10 cm
ensic
cm
20 cm
Fig. 22.30
Answers
Answer:
Big Circle Small Circle Line Rectangle Total
Radius 28 21
Perimeter 176 132 112 420
Area 2464 1386 2352 6202
a) Perimeter
2 x 28 x 22/7 = 176
2 x 21 x 22/7 = 132
28 x 4 = 112
176 + 132 + 112 = 420cm
b) Area
22/7 x 28 x 28 = 2464
22/7 x 21 x 21 = 1386
42 x 56 = 2352
2464 + 1386 + 2352 =6202 cm^2
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stwc
Post on Sun, 25/03/2018 1:41pm
Why did u take 42×56?
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alfretztay
Post on Fri, 13/04/2018 9:17pm
length of the rectangle = 28 + 28 = 56
area of the rectangle = 42 x 56 = 2352
Thus, my solution is a s follows :
Its perimeter = (22/7 x 42) + [(22/7) x (28 + 28)] + (28 x 4) = 420
Its area = [(22/7) x 21 x 21] + [(22/7) x 28 x 28] + [42 x (28 + 28)] = 6202
Ans : Its perimeter = 420 cm; its area = 6202 sq cm.
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Owlinker
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