Question

2352 m + 1386 m + 2464 m2 = 6202
Hence, the area of the total field is 6202 m.
unless otherwise stated.)
the area of each of the following combined figures:
figur
7
he tol
6 cm
22.6
3
16 cm
2
7 cm
O
3
12 cm
I la
4 cm
5 cm
10 cm
ensic
cm
20 cm
Fig. 22.30​

Answer 1

Answer:

Big Circle Small Circle Line Rectangle Total

Radius 28 21

Perimeter 176 132 112 420

Area 2464 1386 2352 6202

a) Perimeter

2 x 28 x 22/7 = 176

2 x 21 x 22/7 = 132

28 x 4 = 112

176 + 132 + 112 = 420cm

b) Area

22/7 x 28 x 28 = 2464

22/7 x 21 x 21 = 1386

42 x 56 = 2352

2464 + 1386 + 2352 =6202 cm^2

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stwc

Post on Sun, 25/03/2018 1:41pm

Why did u take 42×56?

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alfretztay

Post on Fri, 13/04/2018 9:17pm

length of the rectangle = 28 + 28 = 56

area of the rectangle = 42 x 56 = 2352

Thus, my solution is a s follows :

Its perimeter = (22/7 x 42) + [(22/7) x (28 + 28)] + (28 x 4) = 420

Its area = [(22/7) x 21 x 21] + [(22/7) x 28 x 28] + [42 x (28 + 28)] = 6202

Ans : Its perimeter = 420 cm; its area = 6202 sq cm.

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Owlinker

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