Question

23rd one plzzzzzzzzzzzz

Answer 1

$4 {p}^{2} + 6pq + 9 {q}^{2} = {(2p + 3q})^{2} \\ 4 {p}^{2} - 6pq + 9 {q}^{2} = {(2p - 3q)}^{2} \\ hence \: eq \: becomes \: \\ (2p - 3q)(2p + 3q)(2p + 3q \: + 2p - 3q) \\ = \\ 4 {p}^{2} - 9 {q}^{2} (4p)$

Answer 2

Here is your answer in the attachment
Option (A) is your answer

Hope it helps you