(23x_1)+10)÷7=6 value of x
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Given ,
{2^(3x-1) +10 } ÷7 = 6
=> { 2^(3x-1) +10 } = 42
=> { ( 2^3x ) ÷ 2 + ( 20 ÷2 )} =42
=> (2^3x +20)÷2 =42
=> (2^3x +20) = 84
=> 2^3x = 64
=> 2^3x = 2^6
=> 3x=6 { Exponents are equal when equal bases with
{2^(3x-1) +10 } ÷7 = 6
=> { 2^(3x-1) +10 } = 42
=> { ( 2^3x ) ÷ 2 + ( 20 ÷2 )} =42
=> (2^3x +20)÷2 =42
=> (2^3x +20) = 84
=> 2^3x = 64
=> 2^3x = 2^6
=> 3x=6 { Exponents are equal when equal bases with
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