Math, asked by dineshsaravanan1404, 11 months ago

23x-2y=45 and 3x-4y=1 the value of x​

Answers

Answered by mohsenzadehameen48
0

Answer:

Step-by-step explanation:

Solve for y  in one of the equations then substitute it into the other:

3x-4y=1

3x=4y+1

3x-1=4y

3/4x-1/4=y

Now input that into 32x-2y=45

32x-2(3/4x-1/4)=45

Use Pemdas to solve:

32x-3/2x-1/2=45

30.5x-.5=45

30.5x=45.5

x=1.517

Answered by Pranto8
4

Answer:

Step-by-step explanation:

23x-2y=45 ----(1)

3x-4y=1 ----(2)

(1) ×2=> 46x-4y=90

3x - 4y = 1

- + -

___________

43x = 89

X = 89/43

X = 2.06 ----(3)

Putting (3) in (2)

3(2.06) - 4y = 1

6.18 - 4y = 1

-4y = 1-6.18

y = -5. 18/-4

y = 1.295

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