23x-2y=45 and 3x-4y=1 the value of x
Answers
Answered by
0
Answer:
Step-by-step explanation:
Solve for y in one of the equations then substitute it into the other:
3x-4y=1
3x=4y+1
3x-1=4y
3/4x-1/4=y
Now input that into 32x-2y=45
32x-2(3/4x-1/4)=45
Use Pemdas to solve:
32x-3/2x-1/2=45
30.5x-.5=45
30.5x=45.5
x=1.517
Answered by
4
Answer:
Step-by-step explanation:
23x-2y=45 ----(1)
3x-4y=1 ----(2)
(1) ×2=> 46x-4y=90
3x - 4y = 1
- + -
___________
43x = 89
X = 89/43
X = 2.06 ----(3)
Putting (3) in (2)
3(2.06) - 4y = 1
6.18 - 4y = 1
-4y = 1-6.18
y = -5. 18/-4
y = 1.295
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