24/34+55+sin60÷cos30×quintal=6 prove it please.
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30o and 60oare angles of one of the standard triangles
sin(30o)=12
cos(30o)=√32
sin(60o)=√32
cos(60o)=12
So
sin(60o)⋅cos(30o)+sin(30o)⋅cos(60o)
=(√32)(√32)+(12)(12)=34+14
=1
sin(30o)=12
cos(30o)=√32
sin(60o)=√32
cos(60o)=12
So
sin(60o)⋅cos(30o)+sin(30o)⋅cos(60o)
=(√32)(√32)+(12)(12)=34+14
=1
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