24.5g of H2SO4 PRESENT IN 250ML sol is added to 3g of HCL solution present in 750ml aq sol find the resultant normality
Answers
Answered by
1
Answer:
N1V1+N2V2=N3V3
N1=(24.5/49)*1000/250
=2
N2=3/36.5)*1000/750
=0.109
so 2*250+0.109*750=N3*V3
500+82.19=N3* (V1+V2)
N3=582.19/1000
=582.19*10^-3
Hope it helps....
Similar questions