Physics, asked by sds555, 10 months ago

please
answer needed asap.​

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Answers

Answered by Atαrαh
3

I hope this helps........

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Answered by Anonymous
1

We know that -

Parallel Combination

\color{darkblue}\boxed{\sf \dfrac{1}{R_{eff}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}....so\:on}

And

Series Combination

\color{darkblue}\boxed{\sf R_{eff}=R_1+R_2+R_3...so\:on}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Here in this question -

STEP 1 :

Lower 3 resistors are in series combination so ,

\implies{\sf R_{eq}=2+2+2}

\color{orange}\implies{\sf R_{eq}=6Ω}

STEP 2 :

Upper 3 resistors are in series

\implies{\sf R_{eq}=1+1+1 }

\color{orange}\implies{\sf R_{eq}=3Ω}

STEP 3 :

Now they are in Parallel Combination

\implies{\sf \dfrac{1}{R_{eq}}=\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{1}{6} }

\implies{\sf \dfrac{1}{R_{eq}}=\dfrac{36}{36}}

\color{orange}\implies{\sf R_{eq}=1Ω }

STEP 3 :

They are now in series combination

\implies{\sf R_{eq}=1+1+1 }

\color{red}\implies{\sf R_{eq}=3Ω }

\color{darkblue}\underline{\underline{\sf Answer-}}

Equivalent resistance between point A and B is \color{red}{\sf 3Ω}

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