Question

24. A ball is thrown into a vertical plane from a level ground in such a way that it just crosses the top of
two vertical poles after 1 second and 3 seconds from the projection point. Find the time of flight (in
sec) of the ball.​

Answer 1

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t

′

)

2

t

′

=3s

Total time= 3+2= 5s

Answered By Rummorsboys