Question

24. A bullet of mass 'm,' moving with a speed 'x'
strikes a wooden block of mass 'm' and gets
embedded in it. The speed of the embedded block
will be
​

Answer 1

Explanation:

Answer:

The speed will be m2 x.

Explanation:

ACCORDING TO CONSERVATION OF MOMENTUM,

m1u1+m2u2 = (m1+m2)v

So, Here m1=m1     and  m2=m2

               u=x and v=?

So,m1x+m2*0 = (m1+m2)x

    m1x             = m1x + m2x

    m1x-m1x     = m2x

so final answer is M2X

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Answer 2

Answer:

Explanation:

Answer:

The speed will be m2 x.

Explanation:

ACCORDING TO CONSERVATION OF MOMENTUM,

m1u1+m2u2 = (m1+m2)v

So, Here m1=m1     and  m2=m2

               u=x and v=?

So,m1x+m2*0 = (m1+m2)x

    m1x             = m1x + m2x

    m1x-m1x     = m2x

so final answer is M2X

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