Question

24. A shopkeeper marks an article for Rs. 150. He gives 8% discount for cash payment. How much does a customer have to pay while paying in cash ? ​

Answer 1

Rs. 138

Step-by-step explanation:

150-(8%of 150)

150-12

138

Answer 2

$\star \; {\underline{\boxed{\pink{\pmb{\sf{ \; Given \; :- }}}}}}$

• Marked Price = Rs.150
• Discount % = 8 %

$\star \; {\underline{\boxed{\purple{\pmb{\sf{ \; To \; Find \; :- }}}}}}$

• Selling Price = ?

$\star \; {\underline{\boxed{\orange{\pmb{\sf{ \; SolutioN \; :- }}}}}}$

$\bigstar$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Selling \; Price = \bigg\lgroup \dfrac{100 - Discount \; \%}{100} \bigg\rgroup \times Cost \; Price }}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

$\bigstar$ Calculating the Selling Price :

${\longmapsto{\qquad{\sf{ Selling \; Price = \bigg\lgroup \dfrac{100 - Discount \; \%}{100} \bigg\rgroup \times Cost \; Price }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \bigg\lgroup \dfrac{100 - 8}{100} \bigg\rgroup \times 150 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \bigg\lgroup \dfrac{92}{100} \bigg\rgroup \times 150 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \dfrac{92 \times 150}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \dfrac{92 \times 150}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \dfrac{13800}{100} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Selling \; Price = \cancel\dfrac{13800}{100} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pmb{\red{\frak{ Selling \; Price = ₹ \; 138 }}}}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

$\bigstar$ Therefore :

❛❛ Customer had to pay ₹ 138 for the article . ❜❜

$\\ {\underline{\rule{300pt}{9pt}}}$