Question

24μF धारिता के संधारित्र को आवेशित करने में कितना कार्य करना पड़ेगा जबकि प्लेटों के मध्य विभवान्तर 500V

Answer 1

Work done will be equal to 3 J

Explanation:

We have given capacitance between the plates $C=24\mu F=24\times 10^{-6}F$

Potential difference between the plates V = 500 volt

We have to find the work done

Work done is given by $W=\frac{1}{2}CV^2=\frac{1}{2}\times 24\times 10^{-6}\times 500^2=12\times 25\times 10^{-2}=3J$

So work done will be 3 J

Learn more

https://brainly.in/question/9414915