Question

24. Find the zeroes of the polynomial
p(x) = (x - 2) - (x + 2)​

Answer 1

Step-by-step explanation:

use identities (a-b) (a+b)

p(x)=( x)² - (2)²

x² - 4

ans

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Answer 2

(x-2)²-(x+2)²

(a-b)²-(a+b)²......(1)

(a-b)²= a²+b²-2ab

(a+b)²=a²+b²+2ab

in 1

x²+(2)²-2(x)(2)-x²+(2)²+2(x)(2)

{x²-4x+4}-{x²+4x+4}

{x²-2x-2x+4}-{x²+2x+2x+4}

{x(x-2)-2(x-2)}-{x(x+2)+2(x+2)}

{ (x-2) (x-2) } - { (x+2) (x +2) }

x-2= 0

x= 2

x+2=0

x=(-2)

zeroes are 2 and (-2)