Chemistry, asked by jishnupaul52, 8 months ago

24 gm of methane at S.T.P. occupies a volume of..........lit.

Answers

Answered by kundanconcepts800

0

Answer:

33.6L

Explanation:

1mol of CH4 =16g/mol

So, 16g = 22.4L at STP

24g =( 22.4L/16)×24 = 33.6L

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