Question

24. If tanO =4/3
show that
√1-sinO/√1+sinO=1/3
ها با​

Answer 1

Given

→ tan∅ = 4/3

To Prove

→ √(1 - sin∅)/√(1 + sin∅) = 1/3

Proof

→ tan∅ = Perpendicular/Base = 4/3

So, Perpendicular = 4 and Base = 3.

→ H² = B² + P²

→ H² = 4² + P²

→ H = 5

→ sin∅ = Perpendicular/Hypotenuse = 4/5

L.H.S → √(1 - sin∅)/√(1 + sin∅)

→ √(1 - 4/5)/√(1 + 4/5)

→ √(1/5)/√(9/5)

→ √(1/5 × 5/9)

→ √(1/9)

→ 1/3 = R.H.S

Hence Proved