Computer Science, asked by memonmamnai579, 10 months ago

-24 in 8-bit number in 2's complement ​

Answers

Answered by ibolbam
6

That is why the range of two's complement 8-bit numbers is -128 to 127, because 128 is not representable (it would be 10000000, but the sign bit rule says that would be a negative number). The most negative number is 10000000.

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