24 is divided into two parts such that 7 times the first part added to 5 times the second part makes 146 find each part
Answers
Answered by
3
let x any y be the two parts divided.
1st eqn be
x+y=24
2nd eqn be
7x+5y=146
solving these eqns we get
y=11 and x=13.
so the two parts are 11 and 13
1st eqn be
x+y=24
2nd eqn be
7x+5y=146
solving these eqns we get
y=11 and x=13.
so the two parts are 11 and 13
Answered by
2
let the 2 parts be x and y
x + y = 24
x = 24 - y
7x + 5y = 146
7(24-y) + 5y = 146
168 -7y + 5y = 146
168 - 146 -2y = 0
22 = 2y
y = 22 ÷2 = 11
x = 24 - 11
x = 13
The first part is 13
and second part is 11
x + y = 24
x = 24 - y
7x + 5y = 146
7(24-y) + 5y = 146
168 -7y + 5y = 146
168 - 146 -2y = 0
22 = 2y
y = 22 ÷2 = 11
x = 24 - 11
x = 13
The first part is 13
and second part is 11
Similar questions