24 kg ingot contains 54% iron ore. another 12kg ingot contains 72% iron ore. both are melted to form a 28kg ingot. what will be the percentage of iron ore in the new ingot
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Answer:
60%
Step-by-step explanation:
54% iron ore is present in 24kg ingot. So, (54*24)/100= 12.96kg
Likewise, 72% iron ore is present in 12kg ingot. So, (72*12)/100= 8.64Kg
On applying unitary method,
(24+12)Kg ingot contains (12.96+8.64)Kg iron ore
Therefore, 28Kg would contain (21.6*28)/36= 16.8 Kg iron ore
So, percentage of iron ore in the new ingot is (16.8*100)28= 60%
Hence, 60% is your required answer.
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