Question

(24) LC circuit is made with 25 uF capacitor charged
upto 300 V and an inductor of 10 mH. Then the
energy associated with capacitor at time t = 2 sec.
X is ..................... J.
(Chp.7)
(a) 1125 (b) 112.5 (c) 11.25 (d) 1.125

Answer 1

Answer:

I don't know

Explanation:

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Answer 2

Given:

Voltage $V = 300$ V

Capacitance $C = 25 \times 10^{-6}$ F

Inductance $L = 10 \times 10^{-3}$ H

Time $t = 2$ sec

To Find:

Energy associated with capacitor.

From the formula energy stored in capacitor,

    $U = \frac{1}{2} CV ^{2}$

Here, energy stored in capacitor is independent of time,

    $U = \frac{1}{2} \times 25 \times 10^{-6} \times (300) ^{2}$

    $U = 1.125$ J

Therefore, the energy stored in capacitor 1.125 J