Question

24. Starting from rest at one station, a train attains a
velocity of 40 km/h in 60 seconds. Then it applies
brakes and the velocity comes down to 5 km/h in
5 seconds. What is the acceleration of the train in
both these cases?​

Answer 1

Answer:

Newton's first law of motion

v=u+at

in 1st case

v=40km/h=40×5/18=11.11m/s

u=0

a=?

t=60second

a=(v-u)/t

(11.111-0)/60

0.815m/s²

in 2nd case

u=11.111m/s

v=5km/h=1.388 m/s

t=5sec

a=?

(1.388-11.111)/5

-9.723/5

-1.944m/s²

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