24. The perimeter of a rhombus is 100cm. If one of its diagonals is 14cm, then the area of the rhombus is.
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Answer:
336 sq. cm
Step by Step Explanation:
Perimeter of rhombus
= 2 √d1² + d2²
Where d1 and d2 are diagonals.
∴ 2√d1² + d2² = 100
⇒ √d1² + d2² = 50
⇒ d1² + d2² = 2500
⇒ (14)² + d2² = 2500
⇒ d2² = 2500 – 196 = 2304
∴ d² = √2304 = 48
∴ Area of the rhombus =
1
d1² × d2²
2
∴ Area of the rhombus =
1
14 × 48 = 336 sq.cm
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