Question

24. The radius of the circular part of a hemispherical bowl is 9 cm. find the capacity of 21 such bowls. ​

Answer 1

Given :-

• Radius of the circular part of the hemisphere bowls = 9cm

To find :-

• Capacity of 21 such bowls

Capacity refers to the volume of the shape.

FORMULA TO USE :-

$\dfrac{2}{3} \pi r^{3}$

The capacity of 21 hemisphere bowls will be :-

Volume of 1 hemisphere bowl × 21

Substituting the values,

Volume of 1 hemisphere bowl :-

$\dfrac{2}{3} \times \pi \times 9^{3}$

$\dfrac{2}{3} \times \pi \times 729$

By reducing to the lowest terms :-

$Volume = 2 \times \pi \times 243$

$Volume = 486\pi cm^{3}$

Hence the capacity of 21 bowls will be :-

$21 \times 486\pi cm^{3}$

$Capacity/Volume = 10206\pi cm^{3}$

Some more formulas :-

Volume of cube = a³

Volume of cuboid = length × breadth × height

Volume of cylinder = πr²h

Volume of cone = ⅓ πr²h

Volume of sphere = 4/3 πr³