Question

24. Two point charges + q and +4q are separated by a
distance 6a. Find the point joining the two charges
where the electric field is zero,
​

Answer 1

Hey mate hope it help

Answer :

The electric fiels is zero at P only , if the field due to +Q balance the field due to +4Q

14π∈0.Qx2=14π∈0.4q(6a−x)2

1x2=4(6a−x)2

Taking square root or both sides.

1x=2(6a−x)

On cross multiplying we get,

2x=6a−x

x=2a

Hence the required point is at a distance of 2a from Q

Answer 2

Answer :

The electric fiels is zero at P only , if the field due to +Q balance the field due to +4Q

14π∈0.Qx2=14π∈0.4q(6a−x)2

1x2=4(6a−x)2

Taking square root or both sides.

1x=2(6a−x)

On cross multiplying we get,

2x=6a−x

x=2a

Hence the required point is at a distance of 2a from Q

hope this is helpful for u