24. Weight of an object is 294 N on the surface of the earth. What is its weight at a height of 200 km from the surface of the earth. Radius of the earth= 6400 km.
Answers
Answered by
22
g'= g (1 -2h /r )
mg'= mg (1- 2(200) / 6400 )
294( 6400- 400/6400)
294 ( 6000/6400)
294 ( 60/64 )
mg'= 275.625
mg'= mg (1- 2(200) / 6400 )
294( 6400- 400/6400)
294 ( 6000/6400)
294 ( 60/64 )
mg'= 275.625
Answered by
10
g= Acceleration due to gravity
G=change in g due to height.
r=radius
h=height
G= g (1 -2h /r )
mG= mg (1- 2(200) / 6400 )
294( 6400- 400/6400)
294 ( 6000/6400)
294 ( 60/64 )
mG= 275.625
Weight changes due to height.
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