Question

24. When a mixture of 10 mole of S02, 15 mole of O, was
passed over a catalyst, 8 mole of SO, was formed. The
percentage yield of reaction is
(1) 90%
(2) 80%
(3) 50%
(4) 45%

Answer 1

Answer:

2SO

2

+O

2

⇌2SO

3

2 moles of SO

2

will react with 1 mole of O

2

to form 4 moles of SO

3

.

8 moles of SO

2

will react with 4 moles of O

2

to form 8 moles of SO

3

.

Hence, 10−8=2 moles of SO

2

and 15−4=11 moles of O

2

did not enter into the combination respectively

Explanation:

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