Question

24. Which of the following reagents will react with propene ?
(a) Hot alkaline KMnO4
(6) Sodium metal
3
(c) Cold dilute HNO3
(d) LiAlH4

Answer 1

Answer:

a) Hot alkaline KMnO4..............

Answer 2

(a)Hot alkaline KMNO4

Explanation:

• When propene reacts with hot alkaline Potassium permanganate (KMnO4), it forms Ethanoic acid (CH3COOH) and Formic acid or Methanoic acid (HCOOH) as the product.

Reaction:

CH2​=CH−CH3​ →CH3COOH + HCOOH.

• We can see the above equation, CH2=CH–CH3 (C3H6) Propane is treated with Hot alkaline Potassium permanganate (KMnO4) to form Ethanoic acid and Formic acid.

• Now, the formic acid decomposes to water (H20) and carbon dioxide (CO2)

HCOOH→H2​O+CO2​

This is an oxidative cleavage reaction.

Hence, Propene reacts with hot alkaline KMnO4 to form Ethanoic acid and Formic acid.

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