240J of electric energy flows into a certain light bulb every second , and some energy is transformed into light every while some 'waste' thermal energy is also generated. if 200J of thermal energy is generated each second, what is the efficiency of this bulb?
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Answer:
16.67 percent
Explanation:
efficiency= useful output÷ total input ×100%
useful output = 240 -200
=40÷240×100%
=0.167×100%
=16.67%
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