Question

245 A heavy uniform plank of length L is
suspended by two forces F, and F2 at points
distant and form its ends.
251
FL/8->
L/4->
Plank
TFI
TF2
252
What is the value of F1/F2?
(a) 2/5
(b) 3/5
(c) 2/3
(d) 3/2​

Answer 1

Answer:

This is a torque problem. To balance the plank, the counter clockwise torque must be equal to the clockwise torque. To simplify this problem, let’s assume the length of the plank is 8 meters. The left support is 1 meter from its left end.

L/4 = 2 meters

The right support is 2 meters from the right end. Let the pivot point be at the center of the plank. F1 is 3 meters from this point. F2 is 2 meters from this point.

Counter clockwise torque = F2 * 2

Clockwise torque = F1 * 3

F1 * 3 = F2 * 2

F1/F2 = 2/3

Explanation:

hope it helps you