245 g pure KClo, decomposes to give 48 gº? What
is the % yield of reaction?
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2
Answer:
=
Mass of pure
K
C
l
O
3
Mass of the sample
×
100
=
8.167
10.0
×
100
=
81.7
%
=Mass of pure KClO3Mass of the sample×100=8.16710.0×100=81.7%
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